memCSV

memCSV

</div>
AB

Question

Answer

Coordinate Geometry Terms

Coordinate Geometry Definition - It is one of the branches of geometry where the position of a point is defined using coordinates.

What are the Coordinates?

Coordinates are a set of values which helps to show the exact position of a point in the coordinate plane.

Coordinate Plane Meaning - A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

What is the Distance Formula?

It is used to find the distance between two points situated in A(x1,y1) and B(x2,y2)

What is the distance between (4, 0) and (0, 0)?

4

d = (x1 - x2)

= 4 - 0

= 4

What is the distance between (4, 3) and (4, 0)?

3

d = (x1 - x2) + (y1 - y2)

= (4 - 4) + (3 - 0)

= 0 + 3

= 3

What is the distance between (4, 3) and (0, 0)?

Using previous formula, we get

d = (x1 - x2) + (y1 - y2)

= (4 - 0) + (3 - 0)

= 4 + 3

= 7

But we know from https://www.mathsisfun.com/algebra/distance-2-points.html

If (x1 - x2) + (y1 - y2) is giving a higher value than what is correct,

What can the distance formula be?

Why not square the x component and square the y component, and then reduce it down by using square root?

(x1−x2)2+(y1−y2)2\sqrt{(x1 - x2)^2 + (y1 - y2)^2}(x1−x2)2+(y1−y2)2​

Let’s see if it works…

d=(x1−x2)2+(y1−y2)2d = \sqrt{(x1 - x2)^2 + (y1 - y2)^2} d=(x1−x2)2+(y1−y2)2​

=(4−0)2+(3−0)2 = \sqrt{(4 - 0)^2 + (3 - 0)^ 2}=(4−0)2+(3−0)2​

=16+9= \sqrt{16 + 9}=16+9​

=25= \sqrt{25}=25​

=5= 5=5

What is the distance between (2, -1) and (5, 3)?

What is the most logical way to represent a cartesian point in Python?

A. Use two variables, for e.g. x1 and y1 or x2 and y2

B. Use a single tuple variable

C. None of the above

Choice B.

Tuple is the logical way of doing it Python.

What is the syntax for defining a point (3, 4) as a tuple in Python?

A. (3, 4)

B. tuple(3, 4)

C. Both the above are valid

Choice C.



How can you deconstruct a tuple that represents a point?

If

pointA = (6, 8) # construction

then

x1, y1 = pointA # deconstruction

print(x1, y1) # 6, 8

x1, y1, x2, y2 = (1, 2, 3, 4)

What is the value of x1 and y2?

1 and 4. 

Are you confident of writing the code for Distance between Two Points?



Test yourself at http://j.mp/twoPointsCC

Last updated